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The dissipation factor of a good dielectric material is typically of the order of 0.0002.

So, the correct option is:

0.0002

In a capacitor, the electric charge is stored in both the metal plates and the dielectric material between them. The metal plates accumulate equal and opposite charges, creating an electric field between them. The dielectric material serves to increase the capacitance by reducing the electric field strength between the plates and thereby allowing more charge to be stored for a given voltage.

So, the correct option is:

both (a) and (b)

Among the options provided, the silver plated mica capacitor will typically have the least variation. Silver plated mica capacitors are known for their stability and precision in capacitance value over a wide range of temperatures and frequencies. They are often used in applications where precise and stable capacitance values are required.

So, the correct option is:

Silver plated mica capacitor

In a capacitive circuit, an increase in applied voltage makes a capacitor charge. 

When a voltage is applied to a capacitor in a circuit, the capacitor starts to charge, with the voltage across it increasing over time until it reaches the same voltage as the applied voltage. This process occurs because the capacitor stores energy in the form of an electric field between its plates when charged.

So, the correct option is:

an increase in applied voltage makes a capacitor charge

The statement "The surface integral of the normal component of the electric displacement D over any closed surface equals the charge enclosed by the surface" is associated with Gauss's law in electromagnetism.

So, the correct option is:

Gauss's law

An equipotential surface is one in which all points have the same electric potential. 

So, the correct option is:

same

The time constant of an R-C circuit is defined as the time during which the capacitor charging voltage actually rises to 63.2% of its final value. 

So, the correct option is:

63.2, final

Dielectric strength, which is the maximum electric field a dielectric material can withstand without breaking down, is typically expressed in kilovolts per millimeter (kV/mm). 

So, the correct option is:

kV/mm

To calculate the total charge passing through the lamp, we can use the formula:

\[ Q = I \times t \]

Where:
- \( Q \) is the charge (in coulombs),
- \( I \) is the current (in amperes),
- \( t \) is the time (in seconds).

Given:
- \( I = 2 \) A (current),
- \( t = 200 \) s (time).

Substituting the values into the formula:

\[ Q = 2 \times 200 \]\[ Q = 400 \]

So, the total charge passing through the lamp in that time will be 400 coulombs.

Therefore, the correct option is:

400 C

To calculate the strength of the electric field (\( E \)) between the plates of the capacitor, we can use the formula:

\[ E = \dfrac{V}{d} \]

Where:
- \( V \) is the potential difference (in volts),
- \( d \) is the separation distance between the plates (in meters).

Given:
- \( V = 400 \) V (potential difference),
- \( d = 4 \) mm = \( 4 \times 10^{-3} \) m (separation distance).

Substituting the values into the formula:

\[ E = \dfrac{400}{4 \times 10^{-3}} \]\[ E = \dfrac{400}{0.004} \]\[ E = 100000 \]

So, the strength of the electric field is \( 100 \, \text{kV/m}} \).

Therefore, the correct option is:

100 kV/m