$$^{23}_{11}\text{Na} + ^{1}_{0}\text{n} \; \rightarrow \; ^{24}_{11}\text{Na}$$ The Reaction Above Is

$$^{23}_{11}\text{Na} + ^{1}_{0}\text{n} \; \rightarrow \; ^{24}_{11}\text{Na}$$ The Reaction Above Is