Chemistry 2019 Jamb Examination
Chemistry 2019 Jamb Examination
Question 11
Which of the following metals is the most essential in the regulation of blood volume, blood pressure and osmotic equilibrium?
Sodium plays a vital role in maintaining osmotic balance and regulating both blood pressure and blood volume in the body.
It helps control the movement of water between body compartments and ensures proper nerve and muscle function.
A deficiency or excess of sodium can lead to imbalances such as dehydration, low blood pressure, or hypertension.
It helps control the movement of water between body compartments and ensures proper nerve and muscle function.
A deficiency or excess of sodium can lead to imbalances such as dehydration, low blood pressure, or hypertension.
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Question 12
Which of the following alkaline metals react more quickly spontaneously with water?
Calcium reacts more readily with water than other listed metals like beryllium or magnesium.
The reactivity of Group 2 metals increases down the group, making calcium more reactive than magnesium and beryllium.
When calcium reacts with water, it forms calcium hydroxide and hydrogen gas.
The reactivity of Group 2 metals increases down the group, making calcium more reactive than magnesium and beryllium.
When calcium reacts with water, it forms calcium hydroxide and hydrogen gas.
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Question 13
When chlorine water is exposed to bright sunlight, the following products are formed
Chlorine water decomposes under bright sunlight to form hydrochloric acid (HCl) and oxygen gas (O2).
The reaction occurs because sunlight provides energy to break down the hypochlorous acid intermediate formed in water.
This photochemical reaction is represented as: 2HOCl → 2HCl + O2.
The reaction occurs because sunlight provides energy to break down the hypochlorous acid intermediate formed in water.
This photochemical reaction is represented as: 2HOCl → 2HCl + O2.
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Question 14
Which process(es) is/are involved in the turning of starch iodide paper blue-black by chlorine gas?
Chlorine acts as an oxidising agent and converts iodide ions (I⁻) in the paper to iodine (I2).
The liberated iodine reacts with starch to form the blue-black complex that is observed.
Thus, the colour change occurs through oxidation, not direct attack on the starch.
The liberated iodine reacts with starch to form the blue-black complex that is observed.
Thus, the colour change occurs through oxidation, not direct attack on the starch.
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Question 15
Which of the following is a set of neutral oxides?
Neutral oxides are those that neither react with acids nor bases to form salts.
Nitrous oxide (N2O), water (H2O), and carbon monoxide (CO) are all neutral oxides.
They exhibit no acidic or basic properties under normal conditions.
Nitrous oxide (N2O), water (H2O), and carbon monoxide (CO) are all neutral oxides.
They exhibit no acidic or basic properties under normal conditions.
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Question 16
SO3 is not directly dissolved in water in the industrial preparation of H2SO4 by the contact process because
The direct dissolution of SO3 in water is avoided because it is a violently exothermic reaction.
This can cause the formation of a mist of sulphuric acid, making the process inefficient and unsafe.
Instead, SO3 is first absorbed in concentrated H2SO4 to form oleum, which is then diluted with water.
This can cause the formation of a mist of sulphuric acid, making the process inefficient and unsafe.
Instead, SO3 is first absorbed in concentrated H2SO4 to form oleum, which is then diluted with water.
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Question 17
Which of the following statements does not show Rutherford's account of Nuclear Theory? An atom contains a region
According to Rutherford’s nuclear model, most of the atom’s mass is concentrated in a small nucleus which is positively charged.
Therefore, the atom is mostly empty space where most projectiles pass undeflected.
Statement D is incorrect because the nucleus is not large; it is very small compared to the atom’s total volume.
Therefore, the atom is mostly empty space where most projectiles pass undeflected.
Statement D is incorrect because the nucleus is not large; it is very small compared to the atom’s total volume.
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Question 18
Elements X and Y have electronic configurations 1s22s22p4 and 1s22s22p63s23p1 respectively. When they combine, the formula of the compound formed is
Element X (1s22s22p4) is oxygen with a valency of 2, while Y (1s22s22p63s23p1) is aluminium with a valency of 3.
The compound formed balances charges by combining two aluminium atoms with three oxygen atoms.
Hence, the formula is Al2O3, represented here as Y2X3.
The compound formed balances charges by combining two aluminium atoms with three oxygen atoms.
Hence, the formula is Al2O3, represented here as Y2X3.
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Question 19
By what amount must the temperature of 200cm3 of nitrogen at 27°C be increased to double the pressure if the final volume is 150cm3 (Assume ideality)
Using the ideal gas equation: \(\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2}\).
Given: \(P_2 = 2P_1\), \(V_1 = 200\,cm^3\), \(V_2 = 150\,cm^3\), and \(T_1 = 27°C = 300K\).
Substituting: \(\dfrac{P_1 \times 200}{300} = \dfrac{2P_1 \times 150}{T_2}\).\[T_2 = \dfrac{2 \times 150 \times 300}{200} = 450K\].
Therefore, the temperature rise = 450K − 300K = 150K = 177°C (approx).
Given: \(P_2 = 2P_1\), \(V_1 = 200\,cm^3\), \(V_2 = 150\,cm^3\), and \(T_1 = 27°C = 300K\).
Substituting: \(\dfrac{P_1 \times 200}{300} = \dfrac{2P_1 \times 150}{T_2}\).\[T_2 = \dfrac{2 \times 150 \times 300}{200} = 450K\].
Therefore, the temperature rise = 450K − 300K = 150K = 177°C (approx).
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Question 20
The combustion of carbon(II) oxide in oxygen can be represented by the equation:
2CO + O2 → 2CO2
Calculate the volume of the resulting mixture at the end of the reaction if 50cm3 of carbon(II) oxide was exploded in 100cm3 of oxygen.
2CO + O2 → 2CO2
Calculate the volume of the resulting mixture at the end of the reaction if 50cm3 of carbon(II) oxide was exploded in 100cm3 of oxygen.
From the equation: 2CO + O2 → 2CO2.
2 volumes of CO require 1 volume of O2 to form 2 volumes of CO2.
50cm3 of CO will need 25cm3 of O2, leaving 75cm3 of unreacted O2.
Total volume = 50cm3 CO2 + 75cm3 O2 = 125cm3.
2 volumes of CO require 1 volume of O2 to form 2 volumes of CO2.
50cm3 of CO will need 25cm3 of O2, leaving 75cm3 of unreacted O2.
Total volume = 50cm3 CO2 + 75cm3 O2 = 125cm3.
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'It was not yet closing time but most staff were trooping out of their offices.
The lift was working now and he squeezed himself into it,
breathing with difficulty the body odour emitted by one of the passengers.
He sighed with relief when they got to the ground floor and tumbled out of the lift.'
Ken Saro-Wiwa: A Forest of Flowers.
In the excerpt above, the subject's experience in the lift is
Choose the option nearest in meaning to the underlined. The Governor told the chief that he was only on a routine tour
