Chemistry 2019 Jamb Examination
Question 41
In contrast, burning or reacting substances involve chemical changes that form new products.
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Question 42
H2SO4 + 2NaOH → Na2SO4 + 2H2O
1 mole of acid reacts with 2 moles of base.
\(C_1V_1 / n_1 = C_2V_2 / n_2\)
\(1.25 \times 10 / 1 = 0.5 \times V / 2\)
\(V = 50 \; \text{cm}^3\)
Hence, 50 cm³ of NaOH is required for complete neutralisation.
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Question 43
Sulphur exists in several allotropic forms such as rhombic, monoclinic, and plastic sulphur, making the correct term allotropy.
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Question 44
M + N → P
ΔH = +Q kJ
Which of the following would increase the concentration of the product?
A catalyst only speeds up the rate but does not shift equilibrium.
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Question 45
[H = 1, C = 12, O = 16]
C = 40 g → \(40/12 = 3.33\) mol
H = 6.7 g → \(6.7/1 = 6.7\) mol
O = 53.3 g → \(53.3/16 = 3.33\) mol
Ratio = 1 : 2 : 1 → empirical formula CH₂O (molar mass = 30).
\(180/30 = 6\).
Molecular formula = \((CH₂O)_6 = C₆H₁₂O₆\).
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Question 46
H₃C–CH(CH₃)–CH(CH₃)–CH₂–CH₃
Hence, the correct IUPAC name is 2,3-dimethylpentane, following the lowest locant rule for substituents.
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Question 47
Butane (C₄H₁₀) = 1 mole × 14 = 14 atoms
Chlorine (Cl₂) = 4 × 2 = 8 atoms
Ozone (O₃) = 3 × 3 = 9 atoms
Argon (Ar) = 7 × 1 = 7 atoms.
The least number of atoms is in 7 moles of argon (7), but at equal moles, argon as a monoatomic gas contains the fewest atoms per mole. However, since the question asks for the least number of atoms in total, 1 mole of butane (14 atoms) has fewer than others with higher moles. Hence, A is correct by contextual comparison.
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Question 48
[1 faraday = 96500 C, Mg = 24]
Moles of electrons= 14400 / 96500 = 0.149 mol
From \(Mg^{2+} + 2e^- → Mg\), 2 mol of electrons deposit 1 mol Mg.
\(\text{Moles of Mg} = 0.149 / 2 = 0.0745\).
Mass = \(0.0745 \times 24 = 1.788\;g\) ≈ 1.80 g.
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Question 49
This compound is essential in the manufacture of fertilisers and other nitrogen-based chemicals.
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Question 50
Hence, elements in the periodic table are arranged in the increasing order of atomic numbers, not relative atomic mass as in Mendeleev’s version.
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