Question 11
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Question 12
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Question 13
I. Simple pendulum
II. Fire alarms
III. Thermostat
IV. Bimetallic thermometer
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Question 14
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Question 15
\(G = 6.67 \times 10^{-11} \; \text{Nm}^2\text{kg}^{-2}\)
\(m_1 = 10^{24} \; \text{kg}\)
\(m_2 = 10^{27} \; \text{kg}\)
\(r = 10^{20} \; \text{m}\)
Substituting the values into the formula:\[ F = \frac{6.67 \times 10^{-11} \times 10^{24} \times 10^{27}}{(10^{20})^2} \]\[ F = \frac{6.67 \times 10^{(-11 + 24 + 27)}}{10^{40}} \]\[ F = \frac{6.67 \times 10^{40}}{10^{40}} \]\[ F = 6.67 \; \text{N} \]The calculation results in a force of 6.67 Newtons.
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Question 16
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Question 17
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Question 18

James Chadwick later discovered the neutron in 1932, and Isaac Newton is famous for his work on gravity and laws of motion, not subatomic particles.
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Question 19
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Question 20
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