Graduate Trainee Quantitative Ability Access Bank Job

The average of the first four tests = 72
Total marks for four tests = 4 × 72 = 288
After the fifth test, average = 70
Total marks for five tests = 5 × 70 = 350
Score on the fifth test = 350 − 288 = 62
Hence, his most recent test grade is 62.

The first 15 positive integers are 1 to 15.
Average = \( \dfrac{1 + 15}{2} = 8 \).
Hence, the average is 8.

David had \( d \) dollars = \( 100d \) cents.
He returned with \( c \) cents.
Amount spent = \( 100d − c \) cents.
Therefore, the correct expression is \( 100d − c \).

Copies in 10 seconds = 13
Copies per second = \( \dfrac{13}{10} = 1.3 \)
Copies in 1 hour = \( 1.3 × 3600 = 4680 \)
Hence, the machine produces 4680 copies in one hour.

Discount = \$80 − \$68 = \$12
Rate of discount = \( \dfrac{12}{80} × 100 = 15\% \)
Hence, the rate of discount is 15%.

Let the original price be \( x \).
20% off means the selling price is 80% of \( x \).
\( 0.8x = 70 \Rightarrow x = \dfrac{70}{0.8} = 87.5 \)
Hence, the original price was $87.50.

40% of 16 = \( \dfrac{40}{100} × 16 = 6.4 \)
Hence, 40% of 16 is 6.4.

The number of triangles that can be formed by joining non-adjacent vertices of an \( n \)-sided polygon is given by \( n(n−3)/2 \).
For an octagon (\( n = 8 \)):
\( 8(8−3)/2 = 8 × 5 / 2 = 20 \).
However, the total number of triangles that can be formed using any 3 vertices is \( ^8C_3 = 56 \).
Hence, the number of triangles in an octagon is 56.

Sum of 5 quantities = \( 5 × 6 = 30 \)
Sum of 3 quantities = \( 3 × 8 = 24 \)
Sum of remaining two = \( 30 − 24 = 6 \)
Average of remaining two = \( \dfrac{6}{2} = 3 \)
Hence, the average of the remaining two numbers is 3.

Let the original price be 100.
After a 30% reduction, new price = 70.
Required percentage increase to return to 100%:
\( \dfrac{100−70}{70} × 100 = 42.857\% \)
Hence, it should be increased by 42.857%.