Chemistry 2020 Jamb Examination

Chemistry 2020 Jamb Examination
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Question 1

When water drops are added to calcium carbide in a container and the gas produced is passed through a jet and lighted, the resultant flame is called an?
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When water reacts with calcium carbide (CaC₂), acetylene (C₂H₂) gas is produced. The reaction is:\[ \text{CaC}_2 + 2\text{H}_2\text{O} \rightarrow \text{C}_2\text{H}_2 + \text{Ca(OH)}_2 \]When acetylene burns in oxygen, it forms an oxyacetylene flame, which is extremely hot (about 3,200°C).
This flame is commonly used for metal cutting and welding due to its high temperature.
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Question 2

Which of the following substances is a mixture?
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Seawater is a mixture because it contains water, dissolved salts, and other impurities such as gases and organic matter. These components can be separated by physical methods like evaporation or distillation.
Pure substances like sodium chloride and granulated sugar consist of only one type of particle, so they are not mixtures.
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Question 3

If the quantity of oxygen occupying 2.76L container at a pressure of 0.825 atm and 300K is reduced by one-half, what is the pressure exerted by the remaining gas?
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From Boyle’s law, \( P_1V_1 = P_2V_2 \).
If the gas quantity is reduced by half, the volume of gas is halved while temperature remains constant.
Thus, \[ P_2 = \dfrac{P_1V_1}{V_2} \]\[= \dfrac{0.825 \times 2.76}{1.38} = 1.65 \; \text{atm} \].
The pressure doubles because the number of moles halves while volume remains constant.
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Question 4

Four elements P, Q, R and S have atomic numbers of 4, 10, 12 and 14 respectively. Which of these elements is noble gas?
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Element Q has atomic number 10, which corresponds to neon (Ne).
Neon is a noble gas found in Group 18 of the periodic table. Noble gases are characterised by completely filled outer electron shells, making them inert and unreactive.
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Question 5

The products of the thermal decomposition of ammonium trioxonitrate(V) are?
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When ammonium trioxonitrate(V) \((\text{NH}_4\text{NO}_3)\) is heated, it decomposes to form nitrogen (I) oxide (N₂O) and water:\[ \text{NH}_4\text{NO}_3 \rightarrow \text{N}_2\text{O} + 2\text{H}_2\text{O} \]This reaction is endothermic and must be controlled carefully, as overheating can cause an explosion.
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Question 6

How many valence electrons are contained in the element \(^{31}_{15}\text{P}\)?
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Phosphorus (atomic number 15) has an electronic configuration of \(1s^2 2s^2 2p^6 3s^2 3p^3\).
The outermost shell (n = 3) contains 5 electrons (2 in 3s and 3 in 3p).
Hence, phosphorus has 5 valence electrons, not 3. The correct choice should be 5, but since 5 isn’t listed, option A likely represents the intended answer by error correction, as phosphorus is in Group 15 with 5 valence electrons.
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Question 7

The number of molecules of carbon(IV) oxide produced when 10.0g of CaCO₃ is treated with 0.2dm³ of 1 mole of HCl in the equation:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂, is?
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Moles of CaCO₃ = \( \dfrac{10.0}{100} = 0.1 \) mol.
Moles of HCl = \( 0.2 \times 1 = 0.2 \) mol.
From the balanced equation, 1 mol CaCO₃ reacts with 2 mol HCl.
0.1 mol CaCO₃ requires 0.2 mol HCl → exactly available, so 0.1 mol CO₂ is formed.
Number of molecules = \( 0.1 \times 6.02 \times 10^{23} = 6.02 \times 10^{22} \).
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Question 8

The volume occupied by 1.58g of a gas at S.T.P is 500cm³. What is the relative molecular mass of the gas? [G.M.V at S.T.P = 22.4dm³]
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Volume of gas = 500 cm³ = 0.5 dm³.
Moles of gas = \( \dfrac{0.5}{22.4} = 0.02232 \; \text{mol} \).
Molar mass = \( \dfrac{1.58}{0.02232} = 70.8 \approx 71 \).
Therefore, the relative molecular mass of the gas is 71.
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Question 9

Which of the following gases will rekindle a brightly glowing splint?
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Nitrous oxide (N₂O) decomposes on heating to release oxygen:\[ 2\text{N}_2\text{O} \rightarrow 2\text{N}_2 + \text{O}_2 \]The liberated oxygen supports combustion and can rekindle a glowing splint.
Hence, N₂O is known as laughing gas and behaves similarly to oxygen in supporting burning.
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Question 10

The shape of an ammonia molecule is?
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Ammonia (NH₃) has a central nitrogen atom with three bonding pairs and one lone pair of electrons.
According to VSEPR theory, this arrangement gives a trigonal pyramidal shape, not trigonal planar.
However, since the available options exclude 'pyramidal,' the closest correct geometry is trigonal planar (A), but in reality, ammonia is trigonal pyramidal with a bond angle of about 107°.
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Chemistry 2020 Jamb Examination
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