Chemistry 2008 Jamb Examination

Chemistry 2008 Jamb Examination
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Question 31

Which of the following compounds of trioxonitrate (V) will decompose to give dinitrogen (I) oxide and water when heated?
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On heating, \( NH_4NO_3 \) decomposes to form \( N_2O \) and \( H_2O \).
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Question 32

When a solution of ammonium trioxocarbonate (IV) is added to a solution of an unknown salt, a white precipitate which is soluble in dilute hydrochloric acid but insoluble in ethanoic acid is formed. This indicates the presence of
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The white precipitate soluble in dilute HCl but not in ethanoic acid indicates \( Ca^{2+} \) ions.
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Question 33

Lead is used for making bullets and lead shots because of its
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Lead is very dense, making it suitable for bullets and lead shots.
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Question 34

Which of the following gives a precipitate when treated with \( NaOH \) solution?
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\( AlCl_3 \) reacts with \( NaOH \) to form a white precipitate of \( Al(OH)_3 \).
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Question 35

The most common ores of iron include
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The common ores of iron are magnetite, haematite, and limonite.
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Question 36

The type of isomerism shown by cis- and trans- isomers is
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Cis- and trans- isomers arise due to restricted rotation around a double bond, which is a form of geometrical isomerism.
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Question 37

If the silver mirror test is positive, it indicates the presence of an
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The silver mirror test (Tollens' test) is used to detect aldehydes (alkanals).
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Question 38

If glucose is heated with concentrated tetraoxosulphate (VI) acid, it will be dehydrated to
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Concentrated \( H_2SO_4 \) dehydrates glucose, leaving behind carbon as a residue.
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Question 39

The IUPAC nomenclature for the structure above is

The IUPAC nomenclature for the structure above is
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The correct structure corresponds to 2, 3 - dichloro - 4, 4 - dimethyl hex - 2 - ene based on IUPAC nomenclature rules.
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Question 40

A hydrocarbon X with a molar mass of 26 consists of 92.3% carbon. What is its molecular formula?
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Mass of C = 92.3 g, Mass of H = 7.7 g (per 100 g).\[ \text{Moles of C} = \dfrac{92.3}{12} \approx 7.69, \]\[\quad \text{Moles of H} = \dfrac{7.7}{1} = 7.7 \]\[ \text{Ratio C:H} \approx 1:1 \]\[ \text{Empirical formula} = CH, \;\]\[ \text{Molar mass} = 13 \]\[ \dfrac{26}{13} = 2 \; \]\[\Rightarrow \; \text{Molecular formula} = C_2H_2 \]
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Chemistry 2008 Jamb Examination
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