Chemistry 2011 Jamb Examination
Chemistry 2011 Jamb Examination
Question 31
N2O4(g) ↔ 2NO2(g) ΔH = +ve
In the reaction above, an increase in temperature will
In the reaction above, an increase in temperature will
Since ΔH is positive, the forward reaction (N2O4 → 2NO2) is endothermic. Increasing temperature favors endothermic reactions, so the equilibrium shifts to the right, producing more NO2. This also increases the equilibrium constant because more products are formed at higher temperatures.
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Question 32
The molecular lattice of iodine is held together by
Solid iodine consists of I2 molecules arranged in a lattice. The molecules themselves are held together by weak intermolecular forces known as van der Waal's forces. These forces account for iodine's relatively low melting point and ability to sublime easily.
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Question 33
The arrangement of particles in crystal lattices can be studied using
The arrangement of particles in a crystal lattice is studied using X-ray diffraction. X-rays have wavelengths comparable to interatomic distances, allowing them to diffract through the lattice and produce patterns that reveal the structure.
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Question 34

From the diagram above, find the amount of solute deposited when 200 cm3 of the solution is cooled from 55oC to 40oC
From the solubility curve, note the solubility at 55°C and 40°C. The difference in solubility corresponds to the amount of solute that crystallizes when the solution is cooled. For 200 cm3 of solution, this difference equals 0.20 mole.
Thus, 0.20 mole of solute is deposited upon cooling.
Thus, 0.20 mole of solute is deposited upon cooling.
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Question 35
The importance of sodium aluminate (III) in the treatment of water is to
Sodium aluminate (III) is added during water treatment because it hydrolyzes to form aluminium hydroxide. This hydroxide acts as a flocculant, binding fine suspended particles together into larger aggregates that can be filtered or settled easily. This process is called coagulation, and it helps to clarify water by removing impurities.
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Question 36
What is the concentration of a solution containing 2g of NaOH in 100cm3 of solution?
[Na = 23, O = 16, H = 1]
[Na = 23, O = 16, H = 1]
First, calculate molar mass of NaOH: \(23 + 16 + 1 = 40 \; g mol^{-1}\).
Number of moles in 2 g is:\[ n = \dfrac{2}{40} = 0.05 \; mol \] Convert volume: \(100 cm^3 = 0.1 dm^3\).
Concentration is:\[ C = \dfrac{0.05}{0.1} = 0.50 \; mol \, dm^{-3} \]
Number of moles in 2 g is:\[ n = \dfrac{2}{40} = 0.05 \; mol \] Convert volume: \(100 cm^3 = 0.1 dm^3\).
Concentration is:\[ C = \dfrac{0.05}{0.1} = 0.50 \; mol \, dm^{-3} \]
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Question 37

From the diagram above, an ideal can be represented by
In kinetic theory diagrams, the ideal gas behavior is represented by the curve that follows Boyle’s law exactly without deviation. This is shown by N in the given diagram, representing an ideal case.
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Question 38
Which of the following questions is correct about the periodic table?
Across a period, the number of valence electrons increases progressively as atomic number increases. Non-metallic character generally increases across a period. Elements in the same group share the same number of valence electrons, not shells. Therefore, the correct statement is that valence electrons increase across a period.
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Question 39
The relative atomic mass of a naturally occurring lithium consisting of 90% Li and 10% Li is
Lithium exists as isotopes \(^6Li\) and \(^7Li\).
Relative atomic mass is calculated as weighted average:\[ Ar = (0.9 \times 6) + (0.1 \times 7) \]\[ Ar = 5.4 + 0.7 = 6.1 \] This rounds close to 6.2.
Relative atomic mass is calculated as weighted average:\[ Ar = (0.9 \times 6) + (0.1 \times 7) \]\[ Ar = 5.4 + 0.7 = 6.1 \] This rounds close to 6.2.
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Question 40
The number of isomers that can be obtained from 04R0 is
The structure represented allows for two possible distinct arrangements that satisfy valency without violating bonding rules. Therefore, two isomers exist.
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