Mathematics 2022 Jamb Examination
Question 31

In the diagram above, XY = 8cm and OX = 5cm. Find OZ.
A perpendicular line from the center of a circle to a chord bisects that chord. Therefore, XZ = \(\frac{1}{2}\)XY = \(\frac{1}{2}(8)\) = 4cm.
OX is the radius, given as 5cm. OX, XZ, and OZ form a right-angled triangle (\(\Delta OZX\)).
Using Pythagoras' theorem: \(OZ^2 + XZ^2 = OX^2\)\[OZ^2 + 4^2 = 5^2\]\[OZ^2 + 16 = 25 \implies OZ^2 = 9\]\[OZ = \sqrt{9} = 3\text{ cm}\]
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Question 32
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Question 33
Inverse variation is defined by the relationship \(y = \frac{k}{x}\) or \(xy = k\).
Find the constant k: \(3 \times 4 = 12\), so \(k = 12\).
Now find x when y = 12:\[12x = 12\]\[x = \frac{12}{12} = 1\]
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Question 34
Term 1 (a) = 8. Term 4 = 26.
Using \(U_n = a + (n-1)d\):\[26 = 8 + (4-1)d\]\[26 - 8 = 3d \implies 18 = 3d \implies d = 6\]Now calculate p and q:
p = \(a + d = 8 + 6 = 14\)
q = \(p + d = 14 + 6 = 20\)
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Question 35
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Question 36
This expression follows the difference of two squares pattern: \(x^2 - y^2 = (x - y)(x + y)\).
Rewrite the terms as squares:\[(2a)^2 - (3b)^2\]Factorize using the formula:\[(2a - 3b)(2a + 3b)\]
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Question 37
Use the formula for the union of two sets:\[n(P \cup Q) = n(P) + n(Q) - n(P \cap Q)\]Substitute the given values:\[40 = 20 + 30 - n(P \cap Q)\]\[40 = 50 - n(P \cap Q)\]\[n(P \cap Q) = 50 - 40 = 10\]
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Question 38
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Question 39
When representing inequalities on a number line, a solid (closed) circle indicates that the number itself is included (equal to), and the direction of the arrow indicates if the values are greater than or less than. A solid circle at 2 with the line shaded to the right indicates all values greater than or equal to 2.
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Question 40
Let the original price be x:\[0.80x = 3800\]\[x = \frac{3800}{0.80}\]\[x = \frac{38000}{8} = 4750\]The original price was ₦4,750.00.
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