Physics 2009 Jamb Examination

Physics 2009 Jamb Examination
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Question 1

If a cage containing a truck of coal weighing 750 kg is raised to a height of 90 m in a minute, what is the total power expended?
[g = 10 m/s²]
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Power is the rate of doing work. The work done in lifting an object vertically is given by the product of its weight and height.\[ \text{Work done} = mgh \]Substituting values:\[ = 750 \times 10 \times 90 = 675000 \; \text{J} \]The time taken is 1 minute = 60 s.
Therefore, power is:\[ P = \dfrac{\text{Work done}}{\text{Time}} = \dfrac{675000}{60} = 11250 \; \text{W} \]\[ P = 11.25 \; \text{kW} \]This shows the total power expended while lifting the load is 11.25 kW.
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Question 2

An object of mass 80 kg is pulled on a horizontal rough ground by a force of 500 N. Find the coefficient of static friction.
[g = 10 m/s²]
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For equilibrium on a rough surface, the limiting frictional force equals the applied force when motion is impending.\[ F = \mu R \]Where \( R = mg \) is the normal reaction.
Thus,\[ 500 = \mu (80 \times 10) \]\[ 500 = 800\mu \]\[ \mu = \dfrac{500}{800} = 0.625 \]Therefore, the coefficient of static friction is approximately 0.6.
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Question 3

If a heavy barrel is rolled up a plane inclined at 30° to the horizontal, its velocity ratio will be
Show explanation Expand Question
For an inclined plane, the velocity ratio \( VR = \dfrac{1}{\sin \theta} \).
Given \( \theta = 30° \):\[ VR = \dfrac{1}{\sin 30°} = \dfrac{1}{0.5} = 2 \]Hence, the velocity ratio for a 30° incline is 2.
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Question 4

I. Density of the liquid.
II. Acceleration due to gravity.
III. Type of container of the liquid.
IV. The constituents of the liquid.

Which of the above conditions will NOT affect the pressure of fluid?
Show explanation Expand Question
The pressure at a point in a fluid is given by \( P = h\rho g \), where \( h \) is the depth, \( \rho \) is the density, and \( g \) is acceleration due to gravity.
Pressure depends only on these three factors and not on the shape of the container or the constituents of the liquid, provided the density remains constant.
Therefore, the type of container (III) and constituents of the liquid (IV) do not affect the pressure.
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Question 5

If a load of mass 10 N stretched a cord by 1.2 cm, what is the total work done?
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The work done in stretching a spring or elastic cord is given by:\[ W = \dfrac{1}{2} F x \]Given:
\( F = 10 \; \text{N} \), \( x = 1.2 \; \text{cm} = 0.012 \; \text{m} \)\[ W = \dfrac{1}{2} \times 10 \times 0.012 = 0.06 \; \text{J} \]\[ W = 6.0 \times 10^{-2} \; \text{J} \]Thus, the total work done is 6.0 × 10⁻² J.
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Question 6

I. Diameter of a small ball bearing.
II. Thickness of a piece of paper.
III. Diameter of a measuring cylinder.
IV. Length of a piece of wire.

Which of the above can be measured using a micrometer screw gauge?
Show explanation Expand Question
A micrometer screw gauge is designed to measure very small dimensions with high precision such as the diameter of small spherical objects or thin materials.
It is suitable for measuring the diameter of small ball bearings and the thickness of paper.
It cannot be used for larger measurements like cylinder diameters or wire lengths which require a vernier caliper or metre rule respectively.
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Question 7

What is the acceleration between two points on a velocity–time graph which has coordinates (10 s, 15 m/s) and (20 s, 35 m/s)?
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Acceleration is the rate of change of velocity with time.\[ a = \dfrac{v_2 - v_1}{t_2 - t_1} \]Substituting values:\[ a = \dfrac{35 - 15}{20 - 10} = \dfrac{20}{10} = 2 \; \text{m/s}^2 \] Hence, the acceleration between the two points is 2.00 m/s².
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Question 8

A bullet fired vertically upward from a gun held 2.0 m above the ground reaches its maximum height in 4.0 s. Calculate its initial velocity.
[g = 10 m/s²]
Show explanation Expand Question
At maximum height, the final velocity \( v = 0 \).
Using the equation of motion:\[ v = u - gt \]\[ 0 = u - 10 \times 4 \Rightarrow u = 40 \; \text{m/s} \]The bullet was fired with an initial velocity of 40 m/s to reach its maximum height in 4 seconds.
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Question 9

I. The motion of the tyres of a moving car.
II. The motion of a loaded test tube oscillated vertically.
III. The beating of the heart.
IV. A stone tied to a string and whirled round.
V. The motion of the pistons in a gasoline engine.

Which of the motions above is simple harmonic?
Show explanation Expand Question
Simple harmonic motion (SHM) occurs when an object moves about a mean position under a restoring force proportional to its displacement and directed towards that position.
The oscillation of a loaded test tube vertically and the motion of pistons in an engine are examples of approximate SHM. The beating of the heart also exhibits rhythmic periodic motion akin to SHM.
Therefore, motions II, III, and V exhibit simple harmonic behaviour.
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Question 10

A heating coil rated 1000 W is used to boil off completely 2 kg of boiling water. The time required to boil off the water is _______
[Specific latent heat of vaporisation of water = 2.3 × 10⁶ J/kg]
Show explanation Expand Question
The energy required to boil off the water is given by:\[ Q = mL \]Where \( m = 2 \; \text{kg} \), \( L = 2.3 \times 10^6 \; \text{J/kg} \).\[ Q = 2 \times 2.3 \times 10^6 = 4.6 \times 10^6 \; \text{J} \]Power is defined as energy per unit time:\[ P = \dfrac{Q}{t} \Rightarrow t = \dfrac{Q}{P} \]Substituting \( P = 1000 \; \text{W} \):\[ t = \dfrac{4.6 \times 10^6}{1000} = 4.6 \times 10^3 \; \text{s} \]Therefore, it takes 4.6 × 10³ seconds to completely boil off the water.
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Physics 2009 Jamb Examination
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