Physics 2011 Jamb Examination

Physics 2011 Jamb Examination
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Question 11

The correct expression for the potential at a point distance r from a charge q in an electric field is
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The electric potential \(V\) due to a point charge \(q\) at a distance \(r\) is given by the formula:\[V = \dfrac{q}{4\pi \varepsilon_0 r}\]This follows from the definition of potential as the work done per unit charge in bringing a small positive test charge from infinity to the point in question. The potential decreases inversely with distance from the charge and depends directly on the magnitude of the charge. The constant \(\varepsilon_0\) is the permittivity of free space.
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Question 12

The electrical properties of germanium can be altered drastically by the addition of impurity. This process is referred to as
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Doping is the deliberate introduction of a small amount of impurity atoms into a pure semiconductor such as germanium or silicon to modify its electrical properties. This process increases charge carrier concentration, producing n-type (excess electrons) or p-type (excess holes) materials. Doping is fundamental in the manufacture of diodes, transistors, and integrated circuits.
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Question 13

If the threshold frequency for tungsten is 1.3 × 1015 Hz, what is its work function?
[\(h = 6.6 × 10^{-34}\;Js\)]
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The work function \(\phi\) is given by:\[\phi = h f_0\]Substituting the given values:\[\phi = 6.6 × 10^{-34} × 1.3 × 10^{15}\]\[\phi = 8.58 × 10^{-19}\;J\]The work function represents the minimum energy required to eject an electron from the surface of the metal.
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Question 14

Which of the following will be applied when a metal Y is used to electroplate another metal X in electrolysis?
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In electroplating, the metal to be plated (X) is made the cathode, while the metal used for coating (Y) serves as the anode. The electrolyte contains ions of the coating metal. During electrolysis, metal ions from the anode dissolve into the solution and are deposited on the cathode. Therefore, Y must be the anode to supply ions that plate onto X. A moderate current is used to ensure uniform deposition.
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Question 15

Under which of the following conditions do gases conduct electricity?
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At low pressure, the gas molecules are sufficiently far apart, and when a high potential difference is applied, electrons gain enough energy to ionise the gas atoms. These ions and electrons act as charge carriers, allowing the gas to conduct electricity. Therefore, gases conduct under low pressure and high potential difference.
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Question 16

Two inductors of inductance 4 H and 8 H are arranged in series and a current of 10 A is passed through them. What is the energy stored in them?
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When inductors are connected in series, the effective inductance is the sum of their individual inductances:\[L_{eq} = 4 + 8 = 12\;H\]The energy stored in an inductor is given by:\[E = \dfrac{1}{2} L I^2\]Substituting the given values:\[E = \dfrac{1}{2} × 12 × 10^2 = 6 × 100 = 600\;J\]However, since none of the provided options equals 600 J, and option C (133 J) is not consistent with the correct calculation, the intended answer likely had a unit or typographical inconsistency. The correct energy stored is 600 J.
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Question 17

Which of the following materials has an increase in resistance with temperature?
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Metals have positive temperature coefficients of resistance. As temperature increases, metal atoms vibrate more vigorously, increasing collisions between electrons and atoms. This restricts the flow of electrons, leading to an increase in resistance with temperature.
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Question 18

A radioactive isotope has a decay constant of \(10^{-5}\;s^{-1}\). Calculate its half-life.
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The relationship between half-life \(t_{1/2}\) and decay constant \(\lambda\) is:\[t_{1/2} = \dfrac{0.693}{\lambda}\]Substituting \(\lambda = 10^{-5}\;s^{-1}\):\[t_{1/2} = \dfrac{0.693}{10^{-5}} = 6.93 × 10^4\;s\]Hence, the half-life is 6.93 × 10⁴ seconds.
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Question 19

A certain far-sighted person cannot see objects that are closer to the eye than 50 cm clearly. Determine the power of the converging lens which will enable him to see at 25 cm.
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For a far-sighted person, the near point is at 50 cm, and the desired near point is 25 cm. The lens should form an image of an object at 25 cm at his near point (50 cm). Using the lens formula:\[\dfrac{1}{f} = \dfrac{1}{v} - \dfrac{1}{u}\]\[\dfrac{1}{f} = \dfrac{1}{0.50} - \dfrac{1}{0.25} = 2 - 4 = -2\;m^{-1}\]The negative sign shows a virtual image; therefore, the required power is \(P = -2D\). Since none of the options matches this value, no option is correct.
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Question 20

The eclipse of the sun occurs when the
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A solar eclipse occurs when the moon moves directly between the Earth and the Sun, blocking all or part of the Sun’s light from reaching the Earth. The moon casts a shadow on the Earth, and observers located within the moon’s umbra see a total eclipse. This alignment happens during the new moon phase, and because the moon’s orbit is slightly tilted, solar eclipses do not occur every month.
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Physics 2011 Jamb Examination
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