Question 21
Heat transfer by convection in a liquid is due to the
Convection occurs because heating a fluid (liquid or gas) causes it to expand and become less dense. This less dense, warmer portion of the fluid rises, while the cooler, denser portions sink to take its place. This continuous cycle, known as a convection current, is driven by the variation in density within the liquid.
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Question 22
The distance between two successive crests of a wave is 15cm and the velocity 300ms\(^{-1}\). Calculate the frequency.
The distance between two successive crests is the wavelength (\(\lambda\)).
Given:
\(\lambda = 15\text{cm} = 0.15\text{m}\)
\(v = 300\text{ms}^{-1}\)
Using the wave equation:
\\[ v = f\lambda \\]\\[ f = \frac{v}{\lambda} = \frac{300}{0.15} = 2000\text{Hz} \\]In scientific notation, this is \(2.0 \times 10^3\text{Hz}\).
Given:
\(\lambda = 15\text{cm} = 0.15\text{m}\)
\(v = 300\text{ms}^{-1}\)
Using the wave equation:
\\[ v = f\lambda \\]\\[ f = \frac{v}{\lambda} = \frac{300}{0.15} = 2000\text{Hz} \\]In scientific notation, this is \(2.0 \times 10^3\text{Hz}\).
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Question 23
A boy receives the echo of his clap reflected by a nearby hill 0.8s later. How far is he from the hill? [ speed of sound in air = 340ms\(^{-1}\) ]
For an echo, the sound travels to the hill and back, covering the distance (\(d\)) twice. The total distance is \(2d = v \times t\).
Given:
\(v = 340\text{ms}^{-1}\)
\(t = 0.8\text{s}\)
\\[ 2d = 340 \times 0.8 \\]\\[ 2d = 272 \\]\\[ d = \frac{272}{2} = 136\text{m} \\]
Given:
\(v = 340\text{ms}^{-1}\)
\(t = 0.8\text{s}\)
\\[ 2d = 340 \times 0.8 \\]\\[ 2d = 272 \\]\\[ d = \frac{272}{2} = 136\text{m} \\]
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Question 24
An object is placed 10m from a pinhole camera of length 25cm. Calculate the linear magnification.
Magnification (\(M\)) is the ratio of image distance (\(v\)) to object distance (\(u\)).
Given:
\(u = 10\text{m}\)
\(v = 25\text{cm} = 0.25\text{m}\)
\\[ M = \frac{v}{u} = \frac{0.25}{10} = 0.025 \\]In scientific notation, this is \(2.5 \times 10^{-2}\).
Given:
\(u = 10\text{m}\)
\(v = 25\text{cm} = 0.25\text{m}\)
\\[ M = \frac{v}{u} = \frac{0.25}{10} = 0.025 \\]In scientific notation, this is \(2.5 \times 10^{-2}\).
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Question 25
The focal length of a concave mirror is 2.0cm. If an object is placed 8.0cm from it, the image is at
Using the mirror formula:
\\[ \frac{1}{f} = \frac{1}{u} + \frac{1}{v} \\]Given \(f = 2.0\text{cm}\) and \(u = 8.0\text{cm}\):
\\[ \frac{1}{2} = \frac{1}{8} + \frac{1}{v} \\]\\[ \frac{1}{v} = \frac{1}{2} - \frac{1}{8} = \frac{4 - 1}{8} = \frac{3}{8} \\]\\[ v = \frac{8}{3} \approx 2.67\text{cm} \\]Note: The options in the prompt use 'm' instead of 'cm', but based on the calculation, 2.7cm is the intended answer.
\\[ \frac{1}{f} = \frac{1}{u} + \frac{1}{v} \\]Given \(f = 2.0\text{cm}\) and \(u = 8.0\text{cm}\):
\\[ \frac{1}{2} = \frac{1}{8} + \frac{1}{v} \\]\\[ \frac{1}{v} = \frac{1}{2} - \frac{1}{8} = \frac{4 - 1}{8} = \frac{3}{8} \\]\\[ v = \frac{8}{3} \approx 2.67\text{cm} \\]Note: The options in the prompt use 'm' instead of 'cm', but based on the calculation, 2.7cm is the intended answer.
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Question 26
In a compound microscope, the objective and the eye piece focal lengths are
A compound microscope is designed to produce high magnification of very small objects. To achieve this, both the objective lens and the eyepiece have very short focal lengths. The objective lens forms a real, enlarged image, which is then further magnified by the eyepiece acting as a simple magnifying glass.


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Question 27
When a telescope is in normal use, the final image is at
An astronomical telescope is in 'normal adjustment' when the final image is formed at infinity. This allows the observer to view the image with a relaxed eye (no accommodation), which is comfortable for long periods of observation.
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Question 28
When a negatively charged rod is brought near the cap of a charged gold leaf electroscope which has positive charges, the leaf
The electroscope is initially positive, meaning the leaves are diverged due to mutual repulsion. When a negatively charged rod is brought near the cap, it attracts positive charges from the leaves up to the cap. This reduction in positive charge density in the leaves reduces the repulsive force between them, causing the leaves to collapse.
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Question 29
What charge is stored in a 0.1F capacitor when a 10V supply is connected across it?
The charge (\(Q\)) stored in a capacitor is the product of its capacitance (\(C\)) and the potential difference (\(V\)) across it.
\\[ Q = CV \\]Given:
\(C = 0.1\text{F}\)
\(V = 10\text{V}\)
\\[ Q = 0.1 \times 10 = 1\text{C} \\]
\\[ Q = CV \\]Given:
\(C = 0.1\text{F}\)
\(V = 10\text{V}\)
\\[ Q = 0.1 \times 10 = 1\text{C} \\]
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Question 30
The maximum power transfer occur in a cell when the external resistance is
The Maximum Power Transfer Theorem states that for a power source with a fixed internal resistance, the maximum power is delivered to an external load when the resistance of the load (\(R\)) is exactly equal to the internal resistance (\(r\)) of the source.
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