Question 1
 First, find the radius (\( r \)) of the wire:\[ r = \frac{\text{diameter}}{2} = \frac{y}{2\pi} \] Calculate the cross-sectional area (\( A \)):\[ A = \pi r^2 = \pi \left(\frac{y}{2\pi}\right)^2 = \pi \left(\frac{y^2}{4\pi^2}\right) = \frac{y^2}{4\pi} \] Calculate the stress (\( \sigma \)) using \( \text{Stress} = \frac{\text{Force}}{\text{Area}} \):\[ \sigma = \frac{y^2}{\frac{y^2}{4\pi}} \]\[ \sigma = y^2 \cdot \frac{4\pi}{y^2} = 4\pi \, \text{Nm}^{-2} \]
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Question 2
In options A, B, and D, there is no displacement (the load, pot, and tanker remain stationary), so the work done is zero. When a boy climbs onto a table, he exerts a force to move his body weight through a vertical distance (height), fulfilling the requirement for work to be done against gravity.
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Question 3

The mechanical advantage of the machine shown above
In this case of a wedge, we can consider the dimensions given:
Load distance (height of the machine): 15cm
 Effort distance (movement of the effort): 0.5cm\[ \text{M.A.} = \frac{15}{0.5} = 30.0 \]
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Question 4
When sunlight enters a raindrop, it is refracted, then undergoes total internal reflection at the back of the drop, and is refracted again as it leaves. During these refractions, the white light is separated into its component colours (ROYGBIV) because different wavelengths refract at slightly different angles. Dispersion is the specific term for this separation of white light into a spectrum.
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Question 5
The formula is:\[ C = \frac{Q}{V} \]Given:
Charge \( Q = 30 \, \text{C} \)
Voltage \( V = 5 \, \text{V} \)
\[ C = \frac{30}{5} = 6 \, \text{F} \]The capacitance is 6 Farads.
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Question 6
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Question 7
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Question 8
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Question 9
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Question 10
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Departments......P.........Q..........R
Sales value............... N23,400........
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