General Engineering Test 1 Nddc Scholarship

General Engineering Test 1 Nddc Scholarship
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Question 11

Torque is defined as

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Answer: D. All of these

Torque is defined in several equivalent ways:

  • As the product of force and moment arm (option A),

  • As the turning effect of a force (option B),

  • And mathematically as the cross product of position vector and force (option C):

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Question 12


In the figure above, the coefficient of static friction is 0.5. If the tension in the string is T, the
acceleration of the system in motion is _____ [g = 10 ms-2]

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\[ \text{Given: } \mu = 0.5,\; g = 10 \,\text{m/s}^2,\; m_1 = 3\,\text{kg},\; m_2 = 6\,\text{kg}\]

\[ f = \mu m_1 g = 0.5 \times 3 \times 10 = 15 \,\text{N}\]

\[ \text{For } m_2:\quad m_2 g - T = m_2 a\]

\[ \text{For } m_1:\quad T - f = m_1 a\]

\[ \Rightarrow m_2 g - f = (m_1 + m_2)a\]

\[ a = \dfrac{m_2 g - f}{m_1 + m_2}
= \dfrac{60 - 15}{3 + 6}
= \dfrac{45}{9}
= 5 \,\text{m/s}^2\]  

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Question 13

Resistivity of a wire depends on

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Correct option: B. material

Resistivity (ρ)(\rho) is a property of the material of the wire. It does not depend on the length or cross-sectional area. Those only affect the resistance RR, not the resistivity.

\[R= \rho \dfrac{L}{A}\]

Where:

  • R = resistance

  • \(\rho\) = resistivity (depends on material only)

  • L = length of the wire

  • A = cross-sectional area

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Question 14

If a wire 30cm long is extended to 30.5cm by a force of 300N. Find the strain energy of the wire.

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Given 
Initial length: \( L = 30\,\text{cm} = 0.30\,\text{m} \) 
Extension: \( \Delta L = 30.5\,\text{cm} - 30\,\text{cm} = 0.5\,\text{cm} = 0.005\,\text{m} \) 
Force: \( F = 300\,\text{N} \)
Strain energy stored is given by:\[U = \dfrac{1}{2} F \Delta L = \dfrac{1}{2} \times 300 \times 0.005 = 0.75\,\text{J}\] Correct answer is \textbf{D. 0.75 J}

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Question 15

A metal of volume 40cm3 is heated from 300C to 900C, the increase in volume is______
[Linear expansivity of the metal= 2.0 x 10-5K-1]

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The formula for volume expansion is:\[ \Delta V = 3 \alpha V \Delta T \] Where: $$\alpha = 2.0 \times 10^{-5}$$ $\text{K}^{-1} V = 40 \, \text{cm}^3 $ $$\Delta T = 90^\circ \text{C} - 30^\circ \text{C} = 60 \, \text{K} $$ Substitute into the formula: $$ \Delta V = 3 \times (2.0 \times 10^{-5}) \times 40 \times 60 $$ \[ \Delta V = 6.0 \times 10^{-5} \times 2400 \] \[ \Delta V = 0.144 \, \text{cm}^3 \] \[ \boxed{0.144 \, \text{cm}^3} \]

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Question 16

If the volume of a gas increases steadily as the temperature decreases at constant pressure, the gas obeys

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Correct option: D. pressure law

The pressure law (also known as Gay-Lussac’s law) states that at constant volume, the pressure of a gas is directly proportional to its temperature.

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Question 17

The temperature of the system decreases in an ______.

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Correct option: D. adiabatic expansion.

In an adiabatic expansion, a gas expands without heat exchange with its surroundings (Q = 0). Since the gas does work as it expands and no heat enters the system, its internal energy decreases, which leads to a drop in temperature.

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Question 18

Lenz’s law is a law of the conservation of

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Correct Answer: A. energy
Lenz's law states that the direction of an induced current is such that it opposes the change causing it. This ensures the conservation of energy, preventing the induced current from creating energy out of nothing.

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Question 19

The dimensions of electromotive force are

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Correct Answer is A. ML2T-3I-1

\[ \begin{aligned}
\text{EMF} &= \dfrac{\text{Work done}}{\text{Charge}} \\
          &= \dfrac{ML^2T^{-2}}{IT} \\
          &= ML^2T^{-3}I^{-1}
\end{aligned}\]  

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Question 20

If 16mA of current flows through a conductor in one second, the number of electrons transported per second is

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\[ \begin{aligned}
I &= \dfrac{Q}{t} \Rightarrow Q = I \cdot t \\
Q &= 16\,\text{mA} \times 1\,\text{s} = 16 \times 10^{-3}\,\text{C} \\
e &= 1.6 \times 10^{-19}\,\text{C} \\
n &= \dfrac{Q}{e} = \dfrac{16 \times 10^{-3}}{1.6 \times 10^{-19}} = 1.00 \times 10^{17}
\end{aligned}\]  

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