Chemistry 2007 Jamb Examination

Chemistry 2007 Jamb Examination
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Question 11

Which of the following sets of metals dissolves in dilute HCl?
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Metals above hydrogen in the electrochemical series (e.g. Mg, Sn, Fe) react with dilute HCl, releasing H₂ gas.

Copper is below hydrogen and does not react. Correct option C.

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Question 12

If chlorine is bubbled into water and the resulting yellowish-green solution is exposed to bright sunlight for a while, the solution will decompose giving out:
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Cl₂ + H₂O → HCl + HClO. Under bright sunlight, hypochlorous acid (HClO) decomposes to release O₂, leaving behind HCl.

Correct option A.

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Question 13

H₃PO₄(aq) + H₂O(l) ↔ H₂PO₄⁻(aq) + H₃O⁺(aq), ΔH = -13 kJ at 298 K. In the reaction above, an increase in temperature would:
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Since ΔH is negative, the forward reaction is exothermic. Increasing temperature shifts equilibrium in the endothermic (reverse) direction (Le Chatelier’s principle).

Correct option C.

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Question 14

The reaction that takes place in Daniell's cell is:
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Daniell’s cell involves Zn oxidized to Zn²⁺ and Cu²⁺ reduced to Cu(s). This is a redox reaction.

Correct option B.

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Question 15

What happens when zinc rod is immersed in copper (II) tetraoxosulphate (VI) solution?
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Zinc displaces copper from CuSO₄ because it is more reactive: Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s).

The blue Cu²⁺ colour fades as copper deposits. Correct option A.

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Question 16

C₂H₄(g) + H₂(g) → C₂H₆(g), ΔH = -137 kJ mol⁻¹. The reaction represented above is:

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Since ΔH = -137 kJ mol⁻¹, heat is released during the hydrogenation of ethene, meaning it is exothermic. 

Also,

Since ΔH has a negative value, it implies an exothermic reaction, which means a lot of heat is being liberated or evolved from the system to the environment.

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Question 17

How long would it take to deposit 0.08 g of copper from CuCl₂ solution by passing a current of 0.5 A? [Cu = 64, 1F = 96500 C mol⁻¹]
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Moles of Cu = 0.08/64 = 0.00125 mol.
Cu²⁺ + 2e⁻ → Cu. Electrons needed = 2 × 0.00125 = 0.0025 mol e⁻.
Charge = 0.0025 × 96500 = 241.25 C.
Time = Q/I = 241.25 / 0.5 = 482.5 s ≈ 8 min.
Correct option B.

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Question 18

Tartaric acid is used industrially to:
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Tartaric acid is added to sodium hydrogen carbonate to produce baking powder. It prevents the baking soda from leaving a bitter taste.

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Question 19

The salt formed from strong acid and a strong base is?
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A strong acid + strong base gives a neutral salt, e.g. HCl + NaOH → NaCl + H₂O.

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Question 20

Dissolving some pellets of NaOH in water would result in:
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When NaOH dissolves, it dissociates into Na⁺ and OH⁻ ions. The disorder of the system increases, so entropy increases.

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Chemistry 2007 Jamb Examination
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