Chemistry 2013 Jamb Examination
Chemistry 2013 Jamb Examination
Question 31
The constituent of air that acts as a diluent is
Nitrogen makes up about 78% of the Earth's atmosphere and serves as a diluent for oxygen. Its presence reduces the concentration of oxygen, preventing spontaneous combustion and moderating the rate of oxidation and respiration processes. This balance ensures that living organisms can survive and that combustion does not occur uncontrollably in the atmosphere.
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Question 32
Steam changes the colour of anhydrous cobalt (II) chloride from
Anhydrous cobalt(II) chloride is blue in colour, but when exposed to steam or moisture, it absorbs water molecules to form cobalt(II) chloride hexahydrate, which is pink. This colour change from blue to pink is a reversible reaction and is commonly used as a qualitative test for the presence of water or moisture in substances.
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Question 33
An example of a hygroscopic substance is
Hygroscopic substances are those that absorb moisture from the air without forming a solution. Calcium chloride \(\text{CaCl}_2\) is strongly hygroscopic because it readily attracts and retains water molecules from its surroundings to form hydrated salts. This property makes it useful as a drying agent or desiccant in laboratories and industrial applications.
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Question 34
The presence of an impurity in a substance will cause the melting point to
Impurities disrupt the orderly arrangement of particles in a pure substance, weakening the forces holding them together. As a result, less energy is required to break these forces, leading to a decrease in the melting point. This principle is often used in identifying the purity of a substance — a sharp melting point indicates purity, while a lowered or broadened range suggests impurities.
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Question 35
What volume of carbon (II) oxide is produced by reacting excess carbon with 10 dm³ of oxygen?
The balanced chemical equation for the reaction is:\[ 2C + O_2 \rightarrow 2CO \]From the equation, 1 mole of \(O_2\) produces 2 moles of \(CO\). Therefore, the volume of \(CO\) produced is twice the volume of \(O_2\) used.
Given that \(O_2 = 10\;\text{dm}^3\):\[ \text{Volume of } CO = 2 \times 10 = 20\;\text{dm}^3 \]Thus, 20 dm³ of carbon(II) oxide is formed when 10 dm³ of oxygen reacts with excess carbon.
Given that \(O_2 = 10\;\text{dm}^3\):\[ \text{Volume of } CO = 2 \times 10 = 20\;\text{dm}^3 \]Thus, 20 dm³ of carbon(II) oxide is formed when 10 dm³ of oxygen reacts with excess carbon.
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Question 36
The rate of diffusion of a gas Y is twice that of Z. If the relative molecular mass of Y is 64 and the two gases diffuse under the same conditions, find the relative molecular mass of Z.
According to Graham’s Law of Diffusion:\[ \dfrac{r_Y}{r_Z} = \sqrt{\dfrac{M_Z}{M_Y}} \]Given that \(r_Y = 2r_Z\) and \(M_Y = 64\):\[ 2 = \sqrt{\dfrac{M_Z}{64}} \]Squaring both sides:\[ 4 = \dfrac{M_Z}{64} \]\[ M_Z = 256 \]This result appears inconsistent with the expected trend, as a heavier gas should diffuse slower. Reversing the ratio to represent Z diffusing slower gives:\[ \dfrac{r_Z}{r_Y} = \sqrt{\dfrac{M_Y}{M_Z}} \]\[ \dfrac{1}{2} = \sqrt{\dfrac{64}{M_Z}} \]Squaring both sides:\[ \dfrac{1}{4} = \dfrac{64}{M_Z} \]\[ M_Z = 256 \]This means gas Z has a molecular mass of 256 g/mol, which aligns with a slower diffusion rate under identical conditions.
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Question 37
The radioisotope used in industrial radiography for the rapid checking of faults in welds and castings is
Cobalt-60 is a strong gamma-ray emitter and is widely used in industrial radiography for detecting internal flaws in metal welds and castings. Its high-penetration gamma radiation allows engineers to inspect metal components without cutting or damaging them, ensuring structural integrity in pipelines, aircraft, and pressure vessels.
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Question 38
The shape of the carbon (IV) oxide molecule is
Carbon dioxide \(\text{CO}_2\) consists of a carbon atom doubly bonded to two oxygen atoms (O=C=O). The molecule has two regions of electron density around the central carbon atom, which repel each other to form a bond angle of 180°, resulting in a linear geometry. This arrangement minimises electron repulsion according to the Valence Shell Electron Pair Repulsion (VSEPR) theory, giving \(\text{CO}_2\) its linear shape.
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