Question 111
\(d\) is the distance to the wall (408 m).
\(t\) is the total time taken for the echo to return (2.4 s).
Substituting the values into the formula: \[ v = \frac{2 \times 408}{2.4} \] \[ v = \frac{816}{2.4} \] \[ v = 340 \text{ m/s} \] This calculation assumes that the air temperature and wind conditions are uniform along the path of the sound wave.
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Question 112
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Question 113
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Question 114

Using the diagram above, the effective force pushing it forward at an angle 60º is
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Question 115
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Question 116
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Question 117
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Question 118
The relationship is expressed by the formula: \[ Q = C \Delta T \] Given the parameters in the problem: Thermal capacity (\(C\)) = 400 J K\(^{-1}\)
Initial temperature (\(T_1\)) = 60\(^\circ\)C
Final temperature (\(T_2\)) = 80\(^\circ\)C
First, calculate the change in temperature: \[ \Delta T = T_2 - T_1 = 80 - 60 = 20\, \text{K} \] Now, substitute the values into the heat equation: \[ Q = 400 \times 20 \] \[ Q = 8000\, \text{J} \] Since the options are provided in kilojoules (kJ), we convert the result by dividing by 1000: \[ Q = \frac{8000}{1000} = 8\, \text{kJ} \] This represents the total thermal energy required to increase the temperature of the copper rod through the specified range.
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Question 119
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Question 120
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