Mathematics Test 1 Sat Examination

The correct answer is B. 39.
Observing the plot closely, you can see that Activity 3 is between 35 and 40, and even closer to 40 than to 35. Looking at the list of available options, we see that 39 is the only number between 35 and 40. Hence, the number of students that voted for Activity 3 is 39.

$\frac{75}{300}\times 100=25\%$

$\frac{x^2}{25}=36$
$x^2 = 36 \times 25$
$x^2=6^2\times 5^2$
$x = 30$

Lets break the word problem into bits.
Three more: + 3
8 times a number x: 8x 
is equal to 83
Combining these we have:
8x + 3 = 83

Correct answer: A) With each monthly deposit, the amount in Hana’s bank account increased by $25.

The function is f(t)=100+25t, where:

100 is the starting amount in the account before any deposits.
25t means Hana deposits $25 every month, so each month the account increases by $25.

Therefore, 25 represents the monthly increase due to the fixed deposit.

Total angles in a triangle = 180

Both PQR and STU are right angled triangle, as such T' = Q' = 18^o 
Thus:
T' + S' + U' = 180^o
18^o + S' + 90^o = 180^o
S' = 180^o - 108^o = 72^o

Equation of a straight line is given as:
y = mx + c
Where:
m is the gradient of the straight line
\( m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 9}{8.8 - 0} = -0.909 \)

The y-intercept of the line is 9.4.

Substituting, we have:
y = -0.9x + 9.4
or y = 9.4 - 0.9x.

2.5b + 5(16) = 80
2.5b + 80 = 80
b = 0

Equation of a straight line is given by:
y = mx + c    _____Eq.1
where m = gradient and c the y-intercept.

\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]

x_1 = 0; x_2 = -8; y_1 = -8; y_2 = 0

\[ m = \frac{0 - (-8)}{-8 - 0} = \frac{8}{-8} = -1 \]

So, equation of the line:\[ y = -x + c \]

Using point (0, -8) to find c:\[ -8 = -0 + c \implies c = -8 \]

Therefore, the equation of the line is:\[ y = -x - 8 \]

gradient (m) = -1/3
x = 9, and y = 10

$$\frac{y-10}{x-9}=-\frac{1}{3}$$
$$3y-30=x-9$$

None of the options provided is correct.