Mathematics Test 1 Sat Examination

Mathematics Test 1 Sat Examination
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Question 31

A proposal for a new library was included on an election ballot. A radio show stated that 3 times as many people voted in favor of the proposal as people who voted against it. A social media post reported that 15,000 more people voted in favor of the proposal than voted against it.
Based on these data, how many people voted against the proposal?

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Let x be the number of people who voted against the proposal.
Then, according to the radio show:

Votes in favor = 3x
According to the social media post:\[3x - x = 15,000 \Rightarrow 2x = 15,000 \Rightarrow x = 7,500\]

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Question 32


Note: Figure not drawn to scale.
In the figure, lines m and n are parallel. If x = 6k + 13 and y = 8k − 29, what is the value of z ?

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Because m and n are parallel,  and  line t cuts through them, then x = y
6k + 13 = 8k - 29
(6 - 8)k = -29 - 13
-2k = -42
k = 21
so y = 8(21) - 29 = 168 - 29 = 139
z = 180 - 139 = 41o
​​​​​​

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Question 33

−3x + 21px = 84
In the given equation, p is a constant. The equation has no solution.
What is the value of p ?

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\[ \text{Given: } -3x + 21px = 84 \] Factor out x on the left-hand side: \[ x(-3 + 21p) = 84 \] For the equation to have no solution, the coefficient of x must be zero (so the left becomes 0), but the right-hand side is nonzero.
So: \[ -3 + 21p = 0 \Rightarrow 21p = 3 \Rightarrow p = \dfrac{1}{7} \] Substitute \( p = \dfrac{1}{7} \) back into the equation: \[ x(0) = 84 \Rightarrow 0 = 84 \] This is a contradiction, so the equation has no solution when: \[ \boxed{p = \dfrac{1}{7}} \]
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Question 34

f (x) = (x − 10) (x + 13)
The function f is defined by the given equation. For what value of x does f (x) reach its minimum?

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\[ \text{Given: } f(x) = (x - 10)(x + 13)\]

\[\text{Expand the expression:}\]\[ f(x) = x^2 + 13x - 10x - 130 = x^2 + 3x - 130\]

\[\text{This is a quadratic function of the form }
f(x) = ax^2 + bx + c, \text{ where } a = 1,\ b = 3\]

\[\text{The minimum occurs at:}\]\[ x = \dfrac{-b}{2a} = \dfrac{-3}{2(1)} = -\dfrac{3}{2}\]

\[ \boxed{-\dfrac{3}{2}}\]  

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Question 35

The function f\[f(x)=\dfrac{1}{9}{{(x-7)}^{2}}\] gives a metal ball’s height above the ground f(x), in inches,
x seconds after it started moving on a track, where 0 ≤ x ≤ 10. Which of the following is the best interpretation of the vertex of the graph of
y = f (x) in the xy-plane? 

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\[\text{Given: } f(x) = \dfrac{1}{9}(x - 7)^2\]\[\text{This is a quadratic function in vertex form: } f(x) = a(x - h)^2 + k\]\[\text{Comparing, we have } a = \dfrac{1}{9},\ h = 7,\ k = 0\]\[\text{So, the vertex is at } (7, 0)\]\[\text{Since } a > 0,\ \text{the parabola opens upward, meaning the vertex is a minimum point.}\] 
But from the given options, The vertex represents the moment the ball was at its lowest height.
 

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Question 36

If a new graph of three linear equations is created using the system of equations shown and the equation x + 4y = −16, how many solutions (x, y) will the resulting system of three equations have? 

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From the graph: We see two linear equations already plotted. These two lines intersect at exactly one point, meaning the current system has one solution. Now, we're adding a third equation: \[ x + 4y = -16 \] Rewrite in slope-intercept form to solve for \( y \): \[ x + 4y = -16 \Rightarrow 4y = -x - 16 \Rightarrow y = -\frac{1}{4}x - 4 \] This new line has: \[ \text{Slope } (m) = -\frac{1}{4}, \quad y\text{-intercept } (b) = -4 \] The new line has a different slope from either of the two existing lines, meaning it is not parallel to either. It will intersect each of the original lines at distinct points. Since there is no single point where all three lines intersect simultaneously, the system of three equations has: \[ \boxed{\text{A) Zero solutions}} \]
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Question 37

f (x) = 5,470(0.64)x/12 The function f gives the value, in dollars, of a certain piece of equipment after x months of use. If the value of the equipment decreases each year by p% of its value the preceding year, what is the value of p ?

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\[ \text{Given: } f(x) = 5,470 \cdot (0.64)^{\frac{x}{12}} \] This is an exponential decay function, where: \begin{itemize} \item \( x \) is in months, so \( \frac{x}{12} \) converts to years. \item The annual decay factor is \( 0.64 \). \end{itemize} Therefore, the percentage decrease per year is: \[ p = 100\% - 64\% = \boxed{36\%} \]
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Mathematics test-1 Sat Examination
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