Chemistry 2018 Jamb Examination
Question 31
Number of moles of NaOH = \( \dfrac{2}{40} = 0.05 \) mol.
Volume = 100 cm³ = 0.1 dm³.
Concentration = \( \dfrac{0.05}{0.1} = 0.5 \; \text{mol dm}^{-3} \).
Therefore, the concentration of the solution is 0.50 mol dm⁻³.
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Question 32
Number of atoms = \( 0.25 \times 6.02 \times 10^{23} = 1.505 \times 10^{23} \).
Thus, approximately \( 1.51 \times 10^{23} \) atoms are present in 6.0g of magnesium.
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Question 33
Other isotopes like carbon-14 and iodine-131 are mainly used in biological and medical applications.
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Question 34
This similarity arises because they are diagonally related elements (Be in Group 2 and Al in Group 13).
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Question 35
In the equation shown, the equilibrium constant is given by?
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Question 36
(II) 2NH₃(g) + 3Cl₂(g) → 6HCl(g) + N₂(g)
(III) 4NH₃(g) + 3O₂(g) → 6H₂O(l) + N₂(g)
The reactions represented by the equations above demonstrate the
For example, in equation (I), CuO is reduced to Cu as NH₃ is oxidised to N₂.
Hence, the reactions demonstrate the reducing properties of ammonia.
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Question 37
Na2SO3 + 2HCl → 2NaCl + H2O + SO2
SO₂ decolourises acidified KMnO₄ because it acts as a reducing agent, confirming the reaction involves Na₂SO₃.
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Question 38
When the bottle is opened, CO₂ escapes, producing effervescence and a tangy taste due to weak carbonic acid formation.
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Question 39
I. Petroleum
II. Rubber latex
III. Vulcanizer’s solution
IV. Carbon sulphide
Carbon disulphide (carbon sulphide) is a pure compound, not a mixture.
Thus, I, II, and III are mixtures.
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Question 40
This law states that matter is neither created nor destroyed in a chemical reaction; atoms are only rearranged.
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