Physics 2019 Jamb Examination

Physics 2019 Jamb Examination
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Question 31

In the molecular explanation of conduction, heat is transferred by the
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Conduction in solids, especially metals, occurs via two mechanisms: the vibration of atoms/molecules in the lattice and the movement of free electrons. In metals, the kinetic energy is rapidly transferred through the material primarily by these highly mobile free electrons, which collide with other electrons and ions, making metals excellent thermal conductors.
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Question 32

The conductivity of gases at low pressure can be termed as
I. hot cathode emission
II. thermo ionic emission
III. cold cathode emission
IV. Field emission
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Gas conductivity at low pressure is often observed in discharge tubes. When the emission of electrons from the cathode occurs due to a high electric field rather than heat, it is termed cold cathode emission (III). If the electric field itself is the primary driver for extracting electrons from the metal surface, it is called field emission (IV). Hot cathode and thermionic emission refer to electron release due to high temperatures.
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Question 33

Which of the following media allow the transmission of sound waves through them?
I. air
II. liquid
III. solids
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Sound is a mechanical longitudinal wave that requires a material medium for propagation. It travels by causing oscillations in the particles of the medium. Because air (gas), liquids (like water), and solids (like steel) all consist of particles that can transmit these vibrations, sound can pass through all three media.
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Question 34

The earth's gravitational field intensity at its surface is about
(G = 6.7 × 10\(^{-11}\) Nm\(^{2}\)/kg\(^{2}\), mass of the earth is 6 × 10\(^{24}\) kg, radius of the earth is 6.4 × 10\(^{6}\) m, g on the earth = 9.8m/s\(^{2}\))
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Gravitational field intensity (g) is defined as the gravitational force per unit mass. At the surface of the Earth, this is numerically equivalent to the acceleration due to gravity. Using the formula:\[ g = \frac{GM}{R^2} \]Using the provided constants:\[ g = \frac{(6.7 \times 10^{-11}) \times (6 \times 10^{24})}{(6.4 \times 10^6)^2} \approx 9.8 \; \text{N/kg} \]Since the value of 'g' is explicitly given as 9.8 m/s² in the prompt, the intensity is 9.8 N/kg.
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Question 35

The following are parts of the eye:
I. Retina
II. Pupil
III. Iris
The correct equivalent in the camera in the same order are
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Comparing the human eye to a camera: [Image comparing anatomy of human eye and camera]
1. The Retina is the light-sensitive surface where the image forms, equivalent to the Film (or sensor).
2. The Pupil is the opening through which light enters, equivalent to the Aperture.
3. The Iris regulates the size of the pupil, equivalent to the Diaphragm which regulates the aperture size.
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Question 36

According to kinetic molecular model, in gases
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In the kinetic theory of gases, molecules are described as being in constant random motion and are separated by distances that are very large compared to their own size. Because of this, they have negligible intermolecular forces and will expand to fill any container they occupy.
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Question 37

A force of 6N acts horizontally on a stationary mass of 2kg for 4s. The kinetic energy gained by the mass is _________
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1. Find acceleration (\( a \)):\[ a = \frac{F}{m} = \frac{6}{2} = 3 \; \text{ms}^{-2} \]2. Find final velocity (\( v \)) after 4s (starting from rest, \( u=0 \)):\[ v = u + at = 0 + (3 \times 4) = 12 \; \text{ms}^{-1} \]3. Calculate Kinetic Energy (\( K.E. \)):\[ K.E. = \frac{1}{2}mv^2 = \frac{1}{2} \times 2 \times 12^2 = 144 \; \text{J} \]
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Question 38

The momentum of a car moving at a constant speed in a circular track
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Momentum (\( p = mv \)) is a vector quantity, meaning it has both magnitude and direction. Even if the speed is constant, the direction of the car's velocity is constantly changing as it moves around the track. Therefore, the momentum vector is also constantly changing. Depending on the chosen coordinate system, the components of momentum can be positive or negative.
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Question 39

A metal rod has a length of 100cm at 200°C. At what temperature will its length be 99.4cm. If the linear expansivity of the material of the rod is 2 × 10\(^{-5}\) C\(^{-1}\)
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Using the linear expansion formula:\[ L_2 = L_1 [1 + \alpha(T_2 - T_1)] \]\[ 99.4 = 100 [1 + (2 \times 10^{-5})(T_2 - 200)] \]\[ 0.994 = 1 + 0.00002(T_2 - 200) \]\[ -0.006 = 0.00002(T_2 - 200) \]\[ T_2 - 200 = \frac{-0.006}{0.00002} = -300 \]\[ T_2 = -300 + 200 = -100^{\circ}\text{C} \]
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Question 40

The lead-acid accumulator consists of
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A lead-acid battery (accumulator) consists of a lead(IV) oxide (\(\text{PbO}_2\)) positive plate and a lead (\(\text{Pb}\)) negative plate.
Image of a lead-acid battery construction
The electrolyte used is a dilute solution of tetraoxosulphate(VI) acid, commonly known as sulphuric acid (\(\text{H}_2\text{SO}_4\)).
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