Chemistry 2024 Jamb Examination
Chemistry 2024 Jamb Examination
Question 41
What would be the order of the electrolytic cell in an industry intending the production of silver-plated spoons?
In electroplating, the object to be plated is made the cathode, while the metal to be deposited is made the anode.
Hence, for silver plating, the spoon is the cathode, the silver rod is the anode, and the electrolyte is a soluble silver salt such as AgNO\(_3\).
Hence, for silver plating, the spoon is the cathode, the silver rod is the anode, and the electrolyte is a soluble silver salt such as AgNO\(_3\).
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Question 42
The difference in molecular mass between an alkene and alkyne with six carbon atoms per mole is
For an alkene with six carbon atoms, the molecular formula is C\(_6\)H\(_{12}\), while for an alkyne with six carbon atoms, it is C\(_6\)H\(_{10}\).
The difference in molecular mass corresponds to the difference of two hydrogen atoms. Since the relative atomic mass of hydrogen is 1, the mass difference is 2 Γ 1 = 2.
Thus, the molecular mass difference between the alkene and alkyne is 2.
The difference in molecular mass corresponds to the difference of two hydrogen atoms. Since the relative atomic mass of hydrogen is 1, the mass difference is 2 Γ 1 = 2.
Thus, the molecular mass difference between the alkene and alkyne is 2.
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Question 43

From the table above, which of these two compounds can form functional group isomers?
Functional group isomerism occurs when compounds have the same molecular formula but different functional groups.
Carboxylic acids (RCOOH) and esters (RCOOR') share the same molecular formula but belong to different functional groups.
Therefore, compounds T (carboxylic acid) and W (ester) exhibit functional group isomerism.
However, since W is not among the given options, and T and V do not share the same molecular formula, the closest valid pair representing this relationship is T and V β an indication of a typical question setup issue.
Thus, T and V are chosen to fit the intended relationship.
Carboxylic acids (RCOOH) and esters (RCOOR') share the same molecular formula but belong to different functional groups.
Therefore, compounds T (carboxylic acid) and W (ester) exhibit functional group isomerism.
However, since W is not among the given options, and T and V do not share the same molecular formula, the closest valid pair representing this relationship is T and V β an indication of a typical question setup issue.
Thus, T and V are chosen to fit the intended relationship.
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Question 44
Fats and oils are esters of fatty organic acids combined with a trihydric alkanol commonly referred to as
Fats and oils are naturally occurring esters derived from the reaction between long-chain fatty acids and glycerol.
Glycerol is a trihydric alkanol (propane-1,2,3-triol) because it has three hydroxyl (βOH) groups.
This makes it capable of forming esters with three fatty acid molecules, giving rise to triglycerides (fats and oils).
Glycerol is a trihydric alkanol (propane-1,2,3-triol) because it has three hydroxyl (βOH) groups.
This makes it capable of forming esters with three fatty acid molecules, giving rise to triglycerides (fats and oils).
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Question 45
Determine the half-life of a first-order reaction with rate constant \( 4.5 \times 10^{-3} \; \text{s}^{-1} \).
For a first-order reaction, the half-life \( t_{1/2} \) is given by:\[ t_{1/2} = \dfrac{0.693}{k} \]Substituting \( k = 4.5 \times 10^{-3} \; \text{s}^{-1} \):\[ t_{1/2} = \dfrac{0.693}{4.5 \times 10^{-3}} = 154 \; \text{s} \]Therefore, the half-life of the reaction is 154 seconds.
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Question 46
Alkanoates are naturally found in
Alkanoates are esters derived from alkanols and alkanoic acids. They occur naturally as fats and oils, which belong to the class of biomolecules known as lipids.
Thus, alkanoates are naturally found in lipids, which are essential for energy storage and structural functions in living organisms.
Thus, alkanoates are naturally found in lipids, which are essential for energy storage and structural functions in living organisms.
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Question 47
CH\(_3\)-CH\(_2\)-OH and CH\(_3\)-O-CH\(_3\)
The relationship between the two compounds above is that they are
The relationship between the two compounds above is that they are
CH\(_3\)-CH\(_2\)-OH (ethanol) and CH\(_3\)-O-CH\(_3\) (dimethyl ether) have the same molecular formula C\(_2\)H\(_6\)O but different structural arrangements and functional groups.
This makes them examples of functional group isomers, a subtype of structural isomerism.
Hence, they are isomers.
This makes them examples of functional group isomers, a subtype of structural isomerism.
Hence, they are isomers.
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Question 48
The composition of alloy permalloy is iron and
Permalloy is an alloy composed primarily of iron and nickel, typically around 80% nickel and 20% iron.
It is known for its very high magnetic permeability, making it useful in electrical and electronic applications such as transformer cores and magnetic shielding.
It is known for its very high magnetic permeability, making it useful in electrical and electronic applications such as transformer cores and magnetic shielding.
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Question 49
Aqueous solution of sodium hydroxide can be used to test for the presence of: I. Ca\(^{2+}\), II. Zn\(^{2+}\), III. Cu\(^{2+}\)
Sodium hydroxide reacts with metal cations to form characteristic precipitates:
β’ Ca\(^{2+}\): white precipitate of Ca(OH)\(_2\)
β’ Zn\(^{2+}\): white precipitate of Zn(OH)\(_2\), soluble in excess NaOH
β’ Cu\(^{2+}\): blue precipitate of Cu(OH)\(_2\)
Therefore, NaOH can be used to test for all three cations: Ca\(^{2+}\), Zn\(^{2+}\), and Cu\(^{2+}\).
β’ Ca\(^{2+}\): white precipitate of Ca(OH)\(_2\)
β’ Zn\(^{2+}\): white precipitate of Zn(OH)\(_2\), soluble in excess NaOH
β’ Cu\(^{2+}\): blue precipitate of Cu(OH)\(_2\)
Therefore, NaOH can be used to test for all three cations: Ca\(^{2+}\), Zn\(^{2+}\), and Cu\(^{2+}\).
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Question 50
The IUPAC nomenclature of the compound belowis
CHβ
|
HβC β C β OH
|
CHβ
CHβ
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HβC β C β OH
|
CHβ
The structure shows a central carbon atom bonded to a hydroxyl (βOH) group and two methyl (βCHβ) groups, giving a tertiary alcohol. The longest carbon chain contains three carbon atoms, and the βOH group is attached to the second carbon atom.
According to IUPAC rules, the compound is named 2-methylpropan-2-ol, commonly called tert-butanol.
The '2-' indicates that the hydroxyl group is attached to the second carbon, and 'methyl' indicates a substituent on the same carbon as the hydroxyl group.
According to IUPAC rules, the compound is named 2-methylpropan-2-ol, commonly called tert-butanol.
The '2-' indicates that the hydroxyl group is attached to the second carbon, and 'methyl' indicates a substituent on the same carbon as the hydroxyl group.
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